1.
6666650 ta+5555550 ta\underbrace{666\ldots66}_{50\text{ ta}} + \underbrace{555\ldots55}_{50\text{ ta}} ni hisoblang.
2.
Hisoblang.

(2,284720):214(12178)\left(2{,}28 - 4\frac{7}{20}\right) : 2\frac{1}{4} - \left(\frac{1}{2} - 1\frac{7}{8}\right)
3.
Oralaridagi masofa 275 km bo'lgan AA va BB shaharlaridan bir vaqtning o'zida bir-biriga qarab motosiklchi va velosipedchi yo'lga chiqdi. Velosipedchi yo'lda 15 daqiqa dam olib motosiklchi tomon yo'lni davom ettirdi. Motosiklchi esa soatiga 50 km tezlik bilan, velosipedchi esa soatiga 20 km tezlik bilan harakatlandi. Ular uchrashgan paytda motosiklchining bosib o'tgan masofasini (km) toping.
4.
To'g'ri burchakli uchburchakning gipotenuzasi 353\sqrt{5} ga teng. Agar uning bir kateti 13313%133\frac{1}{3}\% ga, ikkinchi kateti esa 1623%16\frac{2}{3}\% ga oshirilsa, hosil bo'lgan katetlar yig'indisi 14 ga teng bo'ladi. Uchburchakning yuzini toping.
5.
Hisoblang.

(23)3(1,875)1\left(\frac{2}{3}\right)^{-3} \cdot (1{,}875)^{-1}
6.
Hisoblang.

666666212345654321\sqrt{\frac{666666^2}{12345654321}}
7.
Hisoblang.

74065+2393\sqrt[6]{7 - \sqrt{40}} \cdot \sqrt[3]{\sqrt{5} + \sqrt{2}} \cdot \sqrt[3]{9}
8.
Arifmetik progressiyada a3=a1+a2a_3 = a_1 + a_2 va a1a2a3=384a_1 \cdot a_2 \cdot a_3 = 384 bo'lsa, S10S_{10} ni toping.
9.
Kamayuvchi geometrik progressiyada b1+b2+b3=19b_1 + b_2 + b_3 = 19 va b12+b22+b32=133b_1^2 + b_2^2 + b_3^2 = 133 bo'lsa, dastlabki beshta hadi yig'indisini hisoblang.
10.
Agar xy=4\frac{x}{y} = 4 va y35y \ne -\frac{3}{5} bo'lsa, x+y+3x+6y+6\frac{x + y + 3}{x + 6y + 6} ning qiymatini toping.
11.
Soddalashtiring.

(1x+1y+1xy)(x+y1)1x2+1y2+2xy1x2y2\frac{\left(\frac{1}{x} + \frac{1}{y} + \frac{1}{xy}\right)(x + y - 1)}{\frac{1}{x^2} + \frac{1}{y^2} + \frac{2}{xy} - \frac{1}{x^2y^2}}
12.
Agar cosα=35\cos\alpha = \frac{3}{5} (0<α<π2)\left(0 < \alpha < \frac{\pi}{2}\right) va a=sinαa = \sin\alpha, b=tgαb = \operatorname{tg}\alpha, c=ctgαc = \operatorname{ctg}\alpha bo'lsa, aa, bb, cc larni o'sish tartibida joylashtiring.
13.
Agar cosα+3cosβ=0\cos\alpha + \sqrt{3}\cos\beta = 0 va 2α+β=1802\alpha + \beta = 180^\circ bo'lsa, αβ|\alpha - \beta| ning qiymatini toping.
14.
Tenglamaning haqiqiy ildizlari yig'indisini hisoblang.

4x2x172x2x+2+256=04^{x^2 - x} - 17 \cdot 2^{x^2 - x + 2} + 256 = 0
15.
Tenglamaning haqiqiy ildizlar ko'paytmasini toping. (Agar u bitta bo'lsa, shu ildizini toping.)

23logx3=log32log32x25logx3\frac{2}{3} - \log_x 3 = \log_3 2 \cdot \log_{32} x - \frac{2}{5}\log_{\sqrt{x}} 3
16.
Tenglama nechta butun yechimga ega?

x42027!2026!+2025!x2+2025=0x^4 - \frac{2027!}{2026! + 2025!}x^2 + 2025 = 0
17.
Tenglama nechta butun yechimga ega?

x4x45=20252x^4 - \sqrt{|x| - 45} = 2025^2
18.
Tengsizlik nechta butun yechimga ega?

x27x+10x26x+9<0\frac{x^2 - 7|x| + 10}{x^2 - 6x + 9} < 0
19.
Tengsizlikni qanoatlantiruvchi butun sonlar nechta?

x24x+452x6<0\sqrt{x^2 - 4x + 4} - 5 \cdot \sqrt{2 - x} - 6 < 0
20.
Rasmda f(x)=ax2+bx+xf(x) = ax^2 + bx + x funksiya grafigi tasvirlangan. Parabola uchining koordinatalari (3;5)(3; 5) va OyOy o'qini (0;315)\left(0; 3\frac{1}{5}\right) nuqtada kesib o'tadi. f(18)f(18) ning qiymatini toping.
Savol
21.
Integralni hisoblang.

111x4+x2dx\int_{-1}^{1} \frac{1}{x^4 + x^2}\,dx
22.
Agar 3(3x+4)20=C0x20+C1x19+C2x18++C19x+C203(3x + 4)^{20} = C_0x^{20} + C_1x^{19} + C_2x^{18} + \ldots + C_{19}x + C_{20} tenglik o'rinli bo'lsa, 2019C01918C1+1817C232C17+C1820 \cdot 19 \cdot C_0 - 19 \cdot 18 \cdot C_1 + 18 \cdot 17 \cdot C_2 - \ldots - 3 \cdot 2 \cdot C_{17} + C_{18} ni hisoblang.
23.
Aylananing vatari 8 ga teng, u 9090^\circ li yoyni tortib tursa, aylana radiusini toping.
24.
Quyidagi grafiklardan nechtasi funksiya bo'ladi?
Savol
25.
ABCABC to'g'ri burchakli uchburchakning BB to'g'ri burchak bissektrisasi ACAC gipotenuzani 5\sqrt{5} va 252\sqrt{5} kesmalarga ajratsa, ABCABC to'g'ri burchakli uchburchak yuzini toping.
26.
ABCABC uchburchakning AA va BB uchlaridan ADAD va BEBE bissektrisalar tushirildi. BEBE va ADAD bissektrisalar KK nuqtada kesishadi. Agar AB=6AB = 6, AE=4AE = 4 va EC=8EC = 8 bo'lsa, KDCEKDCE to'rtburchak yuzini toping.
Savol
27.
ABCDABCD trapetsiyaning BCBC va ADAD asoslari mos ravishda 7 va 27 ga, ABAB va CDCD yon tomonlari esa mos ravishda 12 va 16 ga teng bo'lsa, ABCDABCD trapetsiya yuzini toping.
Savol
28.
Muntazam nn burchakning eng kichik diagonallari orasidagi burchak 120120^\circ ga teng bo'lsa, muntazam nn burchakning nechta tomoni bor?
Savol
29.
ABCABC uchburchak dekart koordinatalar sistemasiga joylashtirildi. Uchburchak uchlarining koordinatalari A(1;3)A(1; 3), B(5;1)B(5; 1), C(4;4)C(4; 4) ga teng bo'lsa, bunda ALAL bissektrisa uzunligini toping.
Savol
30.
Muntazam to'rtburchakli piramidaning to'la sirtining yuzi asosining yuzidan 3 marta katta bo'lsa, yon yog'i bilan asos tekisligi orasidagi burchak tangensini toping.
31.
A={60 ning natural bo’luvchilari}A = \{60\text{ ning natural bo'luvchilari}\}, B={48 ning natural bo’luvchilari}B = \{48\text{ ning natural bo'luvchilari}\} bo'lsa, ABA \cap B ning qism to'plamlar sonini toping.
32.
Raqamlar yig'indisi 7 ga teng bo'lgan uch xonali sonlar qog'ozchalarga yozilgan. Bulardan tanlangan son juft son bo'lish ehtimolligini toping.

Topshiriqlar (33-35) va javob variantlari (A-F) ni o'zaro moslashtiring.

33-35.
Rasmda konus ichiga eng katta hajmli silindr ichki chizilgan.
Savol

Javob variantlari:

A)
13\frac{1}{3}
B)
23\frac{2}{3}
C)
1
D)
34\frac{3}{4}
E)
49\frac{4}{9}
F)
29\frac{2}{9}
SavolABCDEF
33.
Silindr asosining radiusini konus asosi radiusiga nisbatini toping.
34.
Silindr balandligini konus balandligiga nisbatini toping.
35.
Silindr hajmini konus hajmiga nisbatini toping.
36.
Tenglamalar sistemasini yeching.

{26x2+42xy+17y2=1010x2+18xy+8y2=6\begin{cases} 26x^2 + 42xy + 17y^2 = 10 \\ 10x^2 + 18xy + 8y^2 = 6 \end{cases}
a) Tenglamalar sistemasi yechimi (x1;y1)(x_1; y_1), (x2;y2)(x_2; y_2), ..., (xn;yn)(x_n; y_n) bo'lsa, tenglamalar sistemasi nechta yechimga ega?
b) xn+ynx_n + y_n ning eng katta qiymatini toping.
37.
Tenglamani yeching.

sin3x+sin32x+sin33x=(sinx+sin2x+sin3x)3\sin^3 x + \sin^3 2x + \sin^3 3x = (\sin x + \sin 2x + \sin 3x)^3
a) Tenglamaning eng kichik musbat ildizini toping.
b) Tenglama [π;π][-\pi; \pi] oraliqda nechta ildizga ega?
38.
f(x)=ax+bcx+df(x) = \frac{ax + b}{cx + d} funksiya OxOx o'qini (3;0)(3; 0) nuqtada kesib o'tadi. Agar f(x)f(x) funksiyaning qiymatlar sohasi E(y)=(;2)(2;)E(y) = (-\infty; 2) \cup (2; \infty) va f(x)=f1(x)f(x) = f^{-1}(x) bo'lsa (f1(x)f^{-1}(x)f(x)f(x) funksiyaning teskari funksiyasi),
a) f(x)f(x) ning aniqlanish sohasiga tegishli bo'lmagan sonni toping.
b) f1(6)f^{-1}(6) ning qiymatini toping.
39.
f(x)=x283x2f(x) = \frac{x^2}{8} - \frac{3x}{2} kvadrat funksiya va x218x+y212y+97=0x^2 - 18x + y^2 - 12y + 97 = 0 aylana tenglamasi berilgan.
Savol
a) Aylana markazi va parabola uchi orasidagi masofani d1d_1 toping.
b) Paraboladan aylanagacha eng qisqa masofa d2d_2 ni toping.
40.
f(x)=2x2+4xf(x) = -2x^2 + 4x va g(x)=x2+px+qg(x) = x^2 + px + q funksiyalar kesishishidan hosil bo'lgan soha yuzi 3227\frac{32}{27} ga teng. Agar x=43x = \frac{4}{3} to'g'ri chiziq chegaralangan sohani teng ikkiga ajratsa,
a) f(x)f(x) va g(x)g(x) funksiyalar kesishish nuqtalari absissalari yig'indisini toping.
b) pqp \cdot q ning qiymatini toping.
41.
ABCABC uchburchakka aylana ichki chizilgan. ABCABC uchburchakning AA uchidan ADAD bissektrisa o'tkazildi. BCBC tomoniga parallel va aylana markazidan o'tuvchi EFEF kesma o'tkazilgan. Agar BC=30BC = 30, EB=8EB = 8 va FC=12FC = 12 bo'lsa,
Savol
a) DCDC kesma uzunligini toping.
b) ABAB va ACAC tomonlari ayirmasi modulini toping.
42.
ABCDABCD kvadrat ichidan PP nuqta olingan. Agar AP=1AP = 1, BP=5BP = 5, PC=7PC = 7 bo'lsa,
Savol
a) PDPD kesma uzunligini toping.
b) Kvadratning yuzini toping.
43.
Rasmda ADFKADFK parallelogram va EG:GC=1:2EG : GC = 1 : 2, DE:EF=2:3DE : EF = 2 : 3 bo'lsin.
Savol
a) EGBC\frac{EG}{BC} ni toping.
b) Agar SABC=242S_{ABC} = 242 bo'lsa, SADFKS_{ADFK} ni toping.
44.
ABAB diametrli radiusi 3 ga teng bo'lgan sfera berilgan. CC va DD nuqtalar sferada joylashgan. DCDC qirrasi o'rtasidan EE nuqta olindi. Sferaga eng katta hajmli ABCDABCD piramida ichki chizilgan bo'lsa,
a) Piramida hajmini toping.
b) AEAE chiziq va asos tekisligi orasidagi burchak sinusini toping.
45.
Silindr shaklidagi yog'och hajmi V=162π cm3V = 162\pi\ cm^3 va yon sirti S=72π cm2S = 72\pi\ cm^2 ga teng. Usta uni yo'nib shar shakliga keltirdi. Sharning hajmi eng katta bo'lsin. (π3\pi \approx 3 deb olinsin.)
a) Kesib olingan shar sirtining yuzini toping.
b) Silindrdan eng katta shar kesib olinganda chiqindi hajmini toping.